1. Three friends divided some bullets equally. After all of them shot 4 bullets the total no. of remaining bullets is equal to that of one has after division. Find the original number divided.
Solution: Let the no of Bullet be X,
There are 3 divided equally each have X/3 bullets.
then 4 bullets shot By each the no of bullet shoted is 4*3=12
then the remaining bullet = the bullet of a person
x-12=x/3,
3x-36=x
2x=36
x=18
Ans:18
2. There are 3 societies a, b, and c. A lent tractors to B and C as many as they had. After some time B gave as many tractors to A and C as many as they have. After sometime c did the same thing. At the end of this transaction each one of them had 24. Find the tractors each originally had.
Answer: A had 39, B had 21, C had 12,
3. there are six cards in which it has two king cards. all cards are turned down and two cards are openeda) what is the possibility to get at least one king.b) what is the possibility to get two kings.
Answer a - 0.5
b - 1/3
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1 comment:
Unless I've misunderstood the wording, the correct answers are:
A --> 3/5
B --> 1/15
For A, compute the chance of *not* picking any kings. The first card turned over has a 4/6 chance of being a non-king. The second card has a 3/5 chance of also not being a king. That multiplies to be 12/30 = 2/5. Thus the opposite probability of getting at least one king is 3/5.
For B, it is simply 2/6 for the first king and 1/5 for the second king = 2/30 = 1/15.
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